if a Є N such that aN={ax:x Є N}, describe the set 3N ∩ 7N
x = 1,2,3,4,.....
So the set aN becomes {a,2a,3a.....}
That means 3N = {3...21,..,42,....} and 7N = {7,14,21,...42,...}
So 3N Ω 7N = {21,42,...} = 21N
Similarly aN Ω bN =[ LCM (a,b)]N
Hope u understood!