if a Є N such that aN={ax:x Є N}, describe the set 3N ∩ 7N

x = 1,2,3,4,.....

So the set aN becomes {a,2a,3a.....}

That means 3N = {3...21,..,42,....} and 7N = {7,14,21,...42,...}

So 3N  Ω 7N = {21,42,...} = 21N

Similarly aN Ω bN =[ LCM (a,b)]N

Hope u understood!

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