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IF A ND B ARE TWO SETS SUCH THAT n(A)=17, n(B)=23 AND n(A U B)=38.
FIND n(A INTERSECTION B) , n(A-B) , n(B-A)

A(intersection)B is 7 A-B is 10 B - A is 16
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Hope it works

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Given : n(AUB)=38 , n(A)=17 & n(B)=23

we know that,
n(AUB) = n(A) + n(B) - n(A intersection B)

38 =17 + 23 - n(A intersection B)

38 = 40 - n(A intersection B)

n(A intersection B) = 40-38 = 2 

n(A-B) = n(A) - n(A intersection B)
n(A-B) = 17 - 2 = 15

n(B-A) = n(B) - n(A intersection B)
n(B-A) = 23 - 2 = 21

hope it helps :) 


 
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THANKS EVERYONE
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Hahahaha

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Given : n(AUB)=38 , n(A)=17 & n(B)=23

we know that,
n(AUB) = n(A) + n(B) - n(A intersection B)

38 =17 + 23 - n(A intersection B)

38 = 40 - n(A intersection B)

n(A intersection B) = 40-38 = 2 

n(A-B) = n(A) - n(A intersection B)
n(A-B) = 17 - 2 = 15

n(B-A) = n(B) - n(A intersection B)
n(B-A) = 23 - 2 = 21

hope it helps :) 
 
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