If a particle is thrown vertically upwards then the ratio of distance covered in 1st half second and 2nd half second of total time of upward journey is

Dear student,

Since the distance travelled in the last second of upward journey = distance travelled in first second of downward journey(the height-time graph is symmetric about the highest point).

So the ratio of the distances will be 1:1.

Hope this information will clear your doubts about topic.

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