If a straight line (3x+4y+5)+k(x+2y-3)=0 is parallel to x-axis then the value of k is 1) 1 2)-3 3)4 4)2 Share with your friends Share 6 Manbar Singh answered this The given equation of line is,3x + 4y + 5 + kx+2y-3 = 0⇒3+kx + 4+2ky + 5-3k = 0Since, the above line is parallel to x-axis, thencoeffcient of x will be 0.So, 3 + k = 0⇒k = -3 7 View Full Answer