If a straight line (3x+4y+5)+k(x+2y-3)=0 is parallel to x-axis then the value of k is 1) 1 2)-3 3)4 4)2

The given equation of line is,3x + 4y + 5 + kx+2y-3 = 03+kx + 4+2ky + 5-3k = 0Since, the above line is parallel to x-axis, thencoeffcient of x will be 0.So, 3 + k = 0k = -3

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