If a three digit number abc is expressed as abc=x+(a+b+c) then x is always divisible by numbers ?
A- 2 and 3
B- 2 and 6
C- 3 and 9
D- 3and 7
This ques. is from playing with numbers. - Divisibility rules- from prac. material.

Dear Student,

abc = 100a + 10b + c x+a+b+c = 100a + 10b + c x = 99a + 9bx = 911a+bSo x is always divisible by 3 and 9 always. so c option is the correct option

Regards,

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