If a trolley accelerates horizontally with acceleration a then bob is displaced backward from its initial vertical position. The angular deflection of bob in equilibrium is

​Q58. If trolley accelerates horizontally with acceleration a then bob is displaced backward from its initial vertical position. The angular deflection of the bob in equilibrium is 
                   
      1   θ   = cos - 1 a g                                                                               2   θ   = sin - 1 a g 3   θ   = cot - 1 a g                                                                               4   θ   = tan - 1 a g

We can see in the image that g cos(theta) component of acceleration of bob is balnced by a sin(theta) component of acceleration of trolley. g sin(theta) and a cos(theta) are in the same direction. Therefore, Net acceleration=g sin(theta) - a cos (theta) Since this is equilibrium condition, a (net) =0 g sin(theta)=a cis(theta) tan (theta)= a/g
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This is the image

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Answer is: Tan^-1 (a/g)

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Here you go... Cheers...

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