if abc are in gp show that a2 b2c2 ALSO IN GP
Since a,b,c are in GP
So, b2=ac.................(1)
Squaring both sides we get
(b2)2=(ac)2
=> b4=a2c2
=> (b2)2=a2c2
So,we get a2,b2,c2 are in GP
So, b2=ac.................(1)
Squaring both sides we get
(b2)2=(ac)2
=> b4=a2c2
=> (b2)2=a2c2
So,we get a2,b2,c2 are in GP