If acceleration of A is 2m/s2which is smaller than acceleration of B then the value of frictional force applied by B on A is:-
a) 50N
b) 20N
c) 10N
d) None of these
Kindly answer sir/mam.
Dear student,
Please find below the solution to the asked query:
As A is sliding on the block B with an acceleration of 2 m/s2 ,Hence there is relative motion between the blocks so the block a is under the action of maximum frictional force which is providing it the acceleration of 2 m/s2.
so the frictional force on A is F = 5 x 2 = 10 N
now, this is also the frictional force acting on the 10 kg block in backward direction.(Action -Reaction pair)
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
Please find below the solution to the asked query:
As A is sliding on the block B with an acceleration of 2 m/s2 ,Hence there is relative motion between the blocks so the block a is under the action of maximum frictional force which is providing it the acceleration of 2 m/s2.
so the frictional force on A is F = 5 x 2 = 10 N
now, this is also the frictional force acting on the 10 kg block in backward direction.(Action -Reaction pair)
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.