if activation energy(Ea) = 94.14 kJ/mol; k = 1.8*10^-1 sec^-1 and T is 313 K
​ What is the value of of frequency factor?

Dear Student 

As we know that, arrhenius equation 

k = A e-EaRTln k = ln A - EaRTlog k = log A - Ea2.303 RTlog A = log k + Ea2.303 RT          = log1.8 × 10-1 +94.14×1000 J mol-12.303 × 8.314 JK-1mol-1× 313 K          = -0.7447 + 15.7081          = 14.9634Therefore A = antilog(14.9634)                        = 9.191 × 1014 s-1 ( apprx)


So, the A = 9.191 x 1014 s-1

Regards

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