if an exterior angle of a triangle is 130 degree and one of the interior opposite angle is 60 degree.find the interior opposite angle.


ACD = ABC + BAC  { exterior angle is equal to sum of interior opposite angle . }130 = 60 + BAC  BAC  = 70.Other interior  angle is 70 deg . Hope this would have cleared your doubt  . 
 

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please sent the answer

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60 + x = 130

x = 130 -60

x = 70

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