IF ANGLE BETWEEN TWO TANGENTS DRAWN FROM A POINT P TO A CIRCLE OF RADIUS A AND CENTER O IS 60 DEGREE THEN PROVE THAT AP = A UNDER ROOT 3.
We have the following situation-
We know that tangent is always perpendicular to the radius at the point of contact.
So, OAP = 90
We know that if 2 tangents are drawn from an external point, then they are equally inclined to the line segment joining the centre to that point.
According to the angle sum property of triangle-
So, in triangle AOP