If ax2+bx+c=0 and bx2+cx+a=0 have a common root, then prove that a+b+c=0 and a=b=c.

Let α is the common root of  ax2+bx+c=0 and bx2+cx+a=0  2++c=0 and 2++a=0α2ab-c2=αbc-a2=1ac-b2From last two we get, α=bc-a2ac-b2so from first and last we get, cb-a22=ab-c2ac-b2

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