if bcos theta =a, then prove that cosec.cot=root of b+a/b-a Share with your friends Share 8 Varun.Rawat answered this We have, b cos θ = a⇒cos θ = ab Now, sin θ = 1 - cos2θ = 1 - a2b2 = b2-a2bNow, cosec θ = 1sin θ = bb2-a2Now, cot θ = cos θsin θ = a/bb2-a2/b = ab2-a2Now, cosec θ + cot θ = bb2-a2 + ab2-a2 = b+ab2-a2 = b+ab+ab-a = b+ab-a 44 View Full Answer