If consecutive whole number from 1 onward are writtern one after another to the right of 1, find the digit at the 41st place.

Dear Student,

Please find below the solution to the asked query:

We know whole numbers ( 1 , 2 ,3 ,4 , . . . )

So,

We write these numbers from 1  , As :

1 , 2 , 3 , 4 , 5 ,6 , 7 ,8, 9 , 10 , 11 , 12 ,13 , 14 ,15 , 16 , 17 , 18 , 19 , 20 , 21 , 22 ,23 , 24 ,25 , 26 , 27 , 28 , 29 , 30 , 31 , 32 ,33 , 34 ,35 , 36 , 37 , 38 , 39 , 40 , 41 .

So,

On 41st  place we get number  = 41                                         ( Ans )


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