if cos 60 degree + sin square45 degree=2 sin square theta,then sec square theta is:

cos60 + sin^2 45 = 1/2 + (1/root2)^2
=1/2 + 1/2
= 2/2
= 1
given cos60 + sin^2 45 = 2 sin^2 theta

So 2 sin^2 theta = 1
sin^2 theta = 1/2
sin theta = 1/ root 2

1/root2 = sin 45
theeta = 45 degree
sec theeta = root 2
sec square theta = 2

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