If cos (81 +θ) = sin (k/3), where 'θ' is an acute angle, then what will be the value of k?
Cos(81+theta)=sin(k/3)
=sin(9-theta)=sin(k/3)
equate the angles, we get
9-theta=k/3
=k=3(9-theta)
Hope I helped
If cos (81 +θ) = sin (k/3), where 'θ' is an acute angle, then what will be the value of k?
Cos(81+theta)=sin(k/3)
=sin(9-theta)=sin(k/3)
equate the angles, we get
9-theta=k/3
=k=3(9-theta)
Hope I helped