if cosec theta=5/3, evaluate 4sec theta-2 tan theta + 5 sin theta/ 20 cos theta - 3 cosec theta + 9 cot theta

Dear student
cosecθ=53=HPB=H2-P2=52-32=4Therefore,sinθ=35cosθ=45tanθ=34cotθ=43secθ=54Now,4secθ-2tanθ+5sinθ20cosθ-3cosecθ+9cotθ=4×54-2×34+5×3520×45-3×53+9×43=5-32+316-5+12=13223=1346

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