if energy required to remove one of the two electrons from He atom is 29.5 eV then what is the value of energy required to convert a helium atom into alpha particle? ?

Dear Student,

The helium atom has two electrons bound to a nucleus with charge Z = 2. The successive removal of the two electrons can be written as

He → He+ + e- → He++ + 2e-

The minimum energy required to remove the first electron from helium is given as  29.5 eV. The second ionization energy can be calculated exactly since He+ is a hydrogen like ion. The second ionization energy of He is the ionization energy of He+.

- E1s (He+) = Z2RH/(2n2)

where RH = 2.178 x 10-18 J (convert into eV).
It can calculated to be 54.4 eV.

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