if f(x) takes two functions = 1-cos2x/2x​2 ( x not equal to zero) and k ( x = 0 ). find value of k if f(x) is continuous at x=0

f(x)=1-cos 2x2x2k   , x = 0; x0Since given function is continuous at x = 0, then      limx0 fx = f0limx01-cos 2x2x2 = klimx02 sin2x2x2 = klimx0sin xx×limx0sin xx = kk = 1

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