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If far point or near point of a person's eye is given how to calculate Power of lens required for the person?

If far point is given take that as the image distance[v]...and object distance[u] as infinity...& if near pt is giiven take 'u' as 25cm, thn use the lens formula to find the focal length....also remember 1infinity=0.....after getting the focal length substitute tht value in the formula 1f to get the power of the lens...

~thnx~

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Can you explain me why this is so?

Thumbs up for you and please explain me the reasons of taking infinity and how to choose which is image distance or object distance if near and far point are given?

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see Nitin....far point of a normal person is infinity rite?yeah we've learnt tht...so we take tht as 'u' when far point of a myopic eye is given.....& always choose the given value as the image distance coz tht is the image formed on retina of a myopic/hypermetropic eye....& 'u' will be 25cm/infinity depending on the question.......

thnks a lot for the thumb up!

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WQERW
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what?????
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  •  find 'u' and 'v' object and image distance
NOTE power normal human eye near point is 25cm and infinity as far point 
one of the values in the q will be given and the other you can assume is the normal human eye .
  • After that, you can apply the lens formula to find the focal length 
  • 1/f=1/v-1/u 
 as you get this focal length now you can calculate by putting in a power formula 
  1. P=1/f if in m or
  2. P=100/f if in cm
  • unit of power is a diopter 
thanks, i hope it helped you...
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