If for a particular solution , deviation in freezing point is 0.73degre , Kf = 5.028K Kg/mol, what is the molaliy of the solution.
- 0.1452
- 23.76
- 132.6
- 0.8766
Depression in freezing point,
ΔTF=0.730C
Molal elevation constant,KF =5.028K kg/mol
Molality of the solution,m=?
According to the relation
ΔTf=KF x m
m =0.73/5.028=0.1452 molal