if half life of a radioactive is T, then the fraction that would remain after a time T/2 is

Dear Student,

h a l f l i f e = \frac{0.693}{λ} T = \frac{0.693}{λ} \Rightarrow λ = \frac{0.693}{T} w e g o t t h e d e c a y c o n s \tan t i n t e r m s o f T N = N_{o} e^{- λ t} n o w t i m e i s T / 2 p u t t h e v a l u e s N = N_{o} e^{- \frac{0.693}{T} \times \frac{T}{2}} N = N_{o} 0.707 0.7070 o f i n t i a l v a l u e w i l l l e f t a f t e r T / 2 t i m e R e g a r d s