If heat of formation of H2O (g) is –58.3 kcal per mole, than heat of formation of H2O (l) is likely to be Share with your friends Share 0 Vartika Jain answered this Dear Student, H2O (g) → H2O(l)The enthalpy of condensation of water, ∆Hcond=-9.72 kcalmol-1∆Hcond=∆Hf(H2O,l) - ∆Hf(H2O,g) or, -9.72=∆Hf(H2O,l) -(-58.3 kcalmol-1)or, ∆Hf(H2O,l) = -58.3 kcalmol-1-9.72 kcalmol-1=-68.02 kcalmol-1 1 View Full Answer