​If heat of formation of H2O (g) is –58.3 kcal per mole, than heat of formation of H2O (l) is likely to be

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H2O (g)  H2O(l)The enthalpy of condensation of water, Hcond=-9.72 kcalmol-1Hcond=Hf(H2O,l) - Hf(H2O,g) or, -9.72=Hf(H2O,l) -(-58.3 kcalmol-1)or,  Hf(H2O,l)  = -58.3 kcalmol-1-9.72 kcalmol-1=-68.02 kcalmol-1

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