if i try to solve it with equation deltaG =deltaH-TdeltaS option 4 is correct but in same equation i put - Chemistry - Thermodynamics and Thermochemistry

Question

if
i try to solve it with equation deltaG =deltaH-TdeltaS option 4 is
correct but in same equation i put T=0 option 3 is correct getting
confused

Vartika Jain · Accepted Answer

Dear Student, ∆G°= ∆H° -T∆S°Now, ∆H°= -38 3 kJ∆S°= -113 JK-1mol-1For a reaction to be sponatneous,∆G°<0i e ∆H° -T∆S°<0or, ∆H° < T∆S°But this is not true in this case, as, -38 3 > -113T So, (1) is incorrect(2) is correct as T at all temperatures will satisgy the condition on non-spontaneityi e ∆G > 0or, -38 3 > -113T (3) Now, 66°C = 273-66= 207 K(3) and (4) both will be incorrect because the reaction is non-spontaneous at all temperatures

if i try to solve it with equation deltaG =deltaH-TdeltaS option 4 is correct but in same equation i put T=0 option 3 is correct getting confused