If in any triangle ABC, angle C=105, angle B=45, a=2, then find b.

 


As, we know that, sum of three angles of a triangle is 180°

therefore, 

A+B+C= 180°

A+45°+105°=180°

A+150°=180°

A=180°-150°

A=30°

now, apply law of sines, 

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cos C= a2+b2-c2/2ab

cos B=a2+c2-b2/2ac

using the formula ,we will get 2 equation

Solve and get answer

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