If in any triangle ABC, angle C=105, angle B=45, a=2, then find b.
As, we know that, sum of three angles of a triangle is 180°
therefore,
A+B+C= 180°
A+45°+105°=180°
A+150°=180°
A=180°-150°
A=30°
now, apply law of sines,
If in any triangle ABC, angle C=105, angle B=45, a=2, then find b.
As, we know that, sum of three angles of a triangle is 180°
therefore,
A+B+C= 180°
A+45°+105°=180°
A+150°=180°
A=180°-150°
A=30°
now, apply law of sines,