If Kw of water at 25oC is 10-14, calculate the standard reduction potential of the following reaction at 25oC - Chemistry - Electrochemistry

Question

If Kw of water at 25oC is
10-14, calculate the standard reduction potential of the
following reaction at 25oC
2H2O + 2e- ------------- H2 +
2OH-
Given 2H+ + 2e---------------
2H2 Eo= 0 0 V

Kumar Sarang · Accepted Answer

At 25 Âº C : $\log K_{w} = n F E^{ο} / 2 303 R T$ where $E^{0} = {E^{0}}_{r e d} - {E^{0}}_{o x i d} = {E^{0}}_{r e d} - 0 0 = {E^{0}}_{r e d}$ Therefore $\log 10^{- 14} = 2 \times 16 91 \times {E^{0}}_{r e d}$ Where 16 91= F/2 303RT thus ${E^{0}}_{r e d} = - 0 4139 V$

If Kw of water at 25oC is 10-14, calculate the standard reduction potential of the following reaction at 25oC. 2H2O + 2e- ------------- H2 + 2OH- Given 2H+ + 2e--------------- 2H2 Eo= 0.0 V.

If K_w of water at 25^oC is 10^-14, calculate the standard reduction potential of the following reaction at 25^oC.

2H₂O + 2e^- ------------- H₂ + 2OH^-

Given 2H⁺ + 2e^--------------- 2H₂ E^o= 0.0 V.