if length, time and energy are fundamental units find the dimension of mass

Dear Student ,
Here in this case let mass be proportional to length , time and energy .
So , M = Ealbtc
Now , [E] = [ ML2T-2 ]  , [l] = [ L ] , [ t ] = [T ]
So , M1L0T0=ML2T-2aLbTcM1L0T0=MaL2a+bT-2a+cEquating LHSand RHS we get ,a=1 ,2a+b=02+b=0b=-2,-2a+c=0-2+c=0c=2Putting the values of a,b,c we get ,M=EL-2T2
Hope this helps you .
Regards
 

  • 7
Let M be proportional to Length,Time and Energy.
=> M=k Ealbtc
E= ( ML2T-2)    l=(L)    t=(T)

M1L0T= ( ML2T-2)(L)b (T)c
              
= MaL2a+bT-2a+c
Equating LHS and RHS,
a=1
2a+b=0   2+b=0   b=-2
-2a+c=0  -2+c=0   c=2
Putting values of a,b and c

 M=( E T/L-2)   ( k is dimensionless.)
 
  • 3
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