If light strikes a surface with a force of 1 2 X 10-6 N, then how is the result modified - Physics - Electromagnetic Waves

Question

If light strikes a surface with a force of 1 2 X 10-6 N,
then how is the result modified if the surface is a perfect
reflector?

Zafar · Accepted Answer

If we consider the particle nature of
light wave , then we can easily assume that when a photon
(particle) of light wave strike whit a surface it will transfer its
momentum to the surface , hence the surface will experience a net
force If the surface is perfectly reflecting then the photon
falling the surface will be reflecting back , hence the change in
momentum will be twice So the force experience by the surface
(Reflecting ) will also be double
Hence force = 2 x 1 2 x 10 6 N
= 2 4 x 10 6 N

If light strikes a surface with a force of 1.2 X 10-6 N, then how is the result modified if the surface is a perfect reflector?

If light strikes a surface with a force of 1.2 X 10^-6 N, then how is the result modified if the surface is a perfect reflector?