If limit cosec x - cot x /x x--> 0 Share with your friends Share 0 Nishima Pasricha answered this limx→0 cosecx-cotxx=lim x→01sinx-cosxsinxx=lim x→01-cosxxsinxLimit at x→0 is of the form 00.So applying L-Hopital's rule, differentiating both numerator and denominator=lim x→0ddx1-cosxddxxsinx=sinxxcosx+sinxStill, limit at x→0 is of the form 00Differentiating again we get,=lim x→0ddxsinxddxxcosx+sinx=cosx-xsinx+cosx+cosxNow, at x→0 limit comes out be 11+1i.e.12Hence, limx→0 cosecx-cotxx comes out to be 12. 0 View Full Answer
