If log 2 to the base 7 =m, then log 28 to the base 49 is equal to-

10. If log₇ 2 = m, then log₄₉ 28 is equal to
(1) $2(1+2m)$
(2) $\frac{1+2m}{2}$
(3) $\frac{2}{1+2m}$
(4) $1+m$