If mx3 +nx2 +x-6 has (x+2)as a factor and leaves a remainder 4 when divided by (x-2) find the value of m and n Share with your friends Share 2 Neha Sethi answered this Dear student If has as a factor and leaves a remainder 4 when divided by find the value of m and nLet the given polynomial be px= mx3 +nx2 +x-6Given (x+2) is a factor of px⇒p-2=0 factor theorem⇒m-23 +n-22 +-2-6=0⇒-8m+4n-2-6=0⇒4n-8m=8⇒n-2m=2 ...1Given: px leaves a reamainder 4 when divided by (x-2)So, p2=4 remainder theorem⇒ m23 +n22 +2-6=4⇒8m+4n-4=4⇒8m+4n=8⇒2m+n=2 ...2Adding 1 and 2 we getn-2m+2m+n=2+2⇒2n=4⇒n=2⇒2-2m=2⇒2-2=2m⇒m=0 Regards 19 View Full Answer