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If n is an A.P such that a₄/a₇ = 2/3, find a₆/a₈...

$\frac{a_{4}}{a_{7}} = \frac{2}{3} \frac{a + 3 d}{a + 6 d} = \frac{2}{3} 3 a + 9 d = 2 a + 12 d a = 3 d N o w \frac{a_{6}}{a_{8}} = \frac{a + 5 d}{a + 7 d} = \frac{3 d + 5 d}{3 d + 7 d} = \frac{8 d}{10 d} = \frac{4}{5}$

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