if n(U)=40, n(AUB)'=12, n(A-B)=10, n(B-A)=14, find n(A) Share with your friends Share 9 Mayank Jha answered this Dear student, n(A∪B) = n(∪) - n(A∪B)' = 40 - 12 = 28We have, n(A∪B) = n(A - B) + n(A∩B) + n(B - A)⇒28 = 10 + n(A∩B) +14⇒n(A∩B) = 28-24 = 4∴n(A) =n(A∩B) + n(A - B) = 4 + 10 = 14 Regards 10 View Full Answer