If nth division of main scale coincide with (n+1)th division of vernier scale, find the least count of the vernier. Given one main scale devision is equal to 'a' unit.

(n+1)VSD=n MSD

1VSD =(n/n+1)MSD

Least count of vernier callipers

= 1MSD - 1 VSD

=[1-(n/n+1)]MSD

=1/n+1MSD

= a/n+1 unit
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In dimension of critical velocity vc, of liquid following through a tube are expressed [nx,Qy,rz]when n,Q are r are coefficient of viscocity of liquid , density of liquid and radius of the tube respectively, then the values of z,y,and z ate given by :
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Let 1 M. S.D be x. Value of (n+1) divisions in Vernier = x *n. =xn. Value of 1 division on Vernier = xn / n+1. As we know, L. C. = 1 M. S. D - 1 V. S. D. = x - xn/n+1 = x/n+1... So, L. C = x/n+1.
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Let 1 M. S.D be x. Value of (n+1) divisions in Vernier = x *n. =xn . Value of 1 division on Vernier = xn / n+1 . As we know, L. C. = 1 M. S. D - 1 V. S. D = x - xn/n+1 = x/n+1... So, L. C = x/n+1.
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