if nth term of an ap is (5n-2) find its first term and common difference. alao find its 19th term

an=5n-2For n=1, a or a1=51-2=3n=2, a or a2=52-2=8Common difference, d=a2-a1=5a19=a+n-1d=3+19-15=3+185=3+90=93

  • 11

first term , a= 5 *1 -2 =3

second term a2 = 5*2-2 = 8

common difference = a2-a1 = 8 -3 = 5

19 th term = 5*19-2 = 93

  • 9

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  • -1

take n = 1 than a=3

then take n=2 than a2=8

then d=5

therefore ap= 3,8.13........

a19=3+(n-1)5

a19=3+85

=88

there fore 19th is 88

i hope ans ur question

  • -5
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