if number of terms in an a.p. is odd then prove that middle term of a.p. is a.m. of first term and last term of that a.p.

Dear student,

Please find below the solution ot the asked query:

Let the first term and common difference of an AP be 'a' and 'd' respectively.Since the number of terms are odd, the nth term is 2n+1So the last term of the AP is given by,   an=a+2n+1-1d=a+2ndThe arithmetic mean of first and last term is,   AM=a1+an2       =a+a+2nd2       =2a+2nd2       =2a+nd2       =a+nd         .....1The middle term if there are 2n+1 terms in AP is,    2n+1+12th term=n+1th termFind n+1th term of the AP   an+1=a+n+1-1d  an+1=a+nd        .....2From 1  and 2, it can be concluded that middle term of an AP consisiting of odd no of terms  is the AM of the first and last term.

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