if o is any point in the interior od triangleABC.PROVE OA +OB+OC>1/2(AB+BC+CA)

 It is such a easy question --===

  • AB < AO + BO ( Sum of 2 sides of triangle is greater than 3)
  • AC < AO + CO ( Sum of 2 sides of triangle is greater than 3)
  • BC < BO + CO ( Sum of 2 sides of triangle is greater than 3)

 NOW ON ADDING LHS AND RHS WE GET -

  • AB + AC + BC < AO + BO + AO + CO + BO + CO
  • AB + AC + BC < 2AO + 2BO + 2CO
  • AB + AC + BC < 2(AO + BO + CO)
  • FINAL ANS = 1/2(AB + AC + BC) < AO + BO + CO

  • 39

nice ans. bro

  • -1
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