If one end of the diameter of the circle x^2+y^2-4x-6y+11=0 is (8,4). Show that the other end is (-4,2)
This question has not been answered yet!
Don't worry! You can check out similar questions with solutions below
- ... diameter of the circle x?+y?-4x-6y+11=0 is (8,4) show that ...
- Show that Line 3x+4y+7=0 touches the Circle x^2+y^2-4x-6y-12 ...
- ... 3x + 4y +7 = 0 touches the circle x^2 +y^2 - 4x -6y-12 =0
- ... of the circle concentric with the circle x+y+4x+6y+11=0 and ...
- ... concentric with the circle x2+ y2+ 4x + 6y+ 11=0 and passing ...