If one root of the equation 2x? - 10x + p = 0 is 2 , then find the value of p ?
2x^2-10x+p=0
As one root is 2 we must substitue it in this equation
2x(2)^2- 10x(2)+ p=0
2x4- 20+ p=0
8-20+P=0
-12+P=0
P=12
THEREFORE, P VALUE IS 12
2x^2-10x+p=0
As one root is 2 we must substitue it in this equation
2x(2)^2- 10x(2)+ p=0
2x4- 20+ p=0
8-20+P=0
-12+P=0
P=12
THEREFORE, P VALUE IS 12