If one root of the equation 2x? - 10x + p = 0 is 2 , then find the value of p ?

2x^2-10x+p=0

As one root is 2 we must substitue it in this equation

2x(2)^2- 10x(2)+ p=0

2x4- 20+ p=0


8-20+P=0

-12+P=0

P=12

THEREFORE, P VALUE IS 12

 

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