If one third of 100 g of 27% aqueous sugar solution is taken in a beaker and 10 g of sugar is added to it, the concentration of the resulting solution will be (1) 48.34% (2) 44.38% (3) 34.84% (4) 43.84%

the initial solution has a mass of 100g.
when 1/3rd o, f the solution is taken, the concentration will remain same. i.e., (100/3)g of the solution has ((27*(100/3))/100)g of sugar. = 9g sugar in 33.33g solution.
Now 10g sugar is added=> new concentration=(( (9+10)/(33.33+10)) *100)=43.8%


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