if ( p+iq)2= x+iy, prove that (p2+q2)2=x2+y2

 (p+iq)2=x+iy  =>  p2-q2+2ipq=x+iy

 =>  x=p2-q2 ; y=2pq

 R.H.S =>  x2+y2=( p2-q2)2+(2pq)2

    =p4+q4-2p2q2+4p2q2

  =p4+q4+2p2q2

  =(p2+q2)2

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