If p(n) is the statement (n)2>100, prove that p(r+1) is true whenever p(r) is true

Let Pr be truePr: r2>100Pr+1:r+12>100L.H.S.r+12=r2+2r+1Since r is antural number sor+12=r2+2r+1>r2r+12>r2Using Prr+12>r2>100r+12>100Hence Pr+1 is true if Pr is true

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