if P(not A) =0.7 , P(B)=0.7 and P(B/A) =0.5 find P(A/B) Share with your friends Share 2 Musab Kazi answered this dude use the frmula p(A/B)= P(AintB)/P(B) P(AunionB)=P(a)+P(B)+P(AintB) -3 View Full Answer Sachin answered this Hope u will get it 10 Abira answered this Hope u got your answer!! 1 Niranjan Hira answered this Solution:-) We have, P(not A) = 0.7, P(B) = 0.7 and P(B/A) = 0.5 Now, P(A) = 1 - P(not A) = 1 - 0.7 = 0.3 P(B/A) = P(A and B) / P(A) P(A and B) = P(B/A) x P(A) = 0.5 x 0.3 = 0.15 Hence, P(A/B) = P(A and) / P(B) = 0.15 / 0.7 = 0.21 .Ans. 3
