If PA and PB are tangents to the circle With Centre O such that angle APB is equal to 50 degree then find Angle B

PA & PB are equal.[the length of two tangents to the circle from an external point are equal.]
therefore, ​APB is a isosceles triangle.
angle PAB= angle PBA [base angles of isoceles triangle]
therefore by angle sum property,
angle PAB= angle PBA= (180-50)/2
                                       =130/2 =65