If pa=qb=rc and pqr=1, prove that 1/a+1/b+1/c=0
Let p^a=q^b=r^c=k
then,log k=logp^a
so,log k=alog p
log k/log p=a-------------------------1
log k=log q^b
so log k=blog q
log k/log q=b---------------------2
log k=log r^c
so log k=clog r
log k/log r=c------------------------3
thus 1/a+1/b+1/c=log p/log k + log q/log k +log r/log k (from 1,2,3)
=(log p +log q+log r )/log k
=log(pqr)/log k
=0/log k (as given pqr is 1)
=0 ,hence proven
then,log k=logp^a
so,log k=alog p
log k/log p=a-------------------------1
log k=log q^b
so log k=blog q
log k/log q=b---------------------2
log k=log r^c
so log k=clog r
log k/log r=c------------------------3
thus 1/a+1/b+1/c=log p/log k + log q/log k +log r/log k (from 1,2,3)
=(log p +log q+log r )/log k
=log(pqr)/log k
=0/log k (as given pqr is 1)
=0 ,hence proven