If pressure of a gas is reduced by 25% then what should be the temperature required to make its volume twice at stp?

Dear Student,

The computation are expressed below,

at STP,P1=1atm,  T1=273 Kat 25% reduction,P2=0.75 atm T2=?P1P2=T1T210.75=273T2T2=204.75 KP1V1P2V2=T1T210.75×V1V2=27204.751.33×V1V2=1.33V1=V2Hence for doubling volume temperature have to be doubled at STP so we get,T=2×273=546 K

Regards.

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