If rate constant of a reaction is 1 6×10^(-5) and 6 36×10^(-3) per second at 600K and 700K, calculate activation - Chemistry - Chemical Kinetics

Question

If rate constant of a reaction is 1 6×10^(-5) and 6
36×10^(-3) per second at 600K and 700K, calculate activation
energy for reaction

Avni · Accepted Answer

Here, k1 = 1 6×10-5 s-1,
k2 = 6 36×10-3 s-1
and T1= 600K and T2 =
700K
ln(k1k2) = (1T2-1T1) EaR

ln(1 6×10-56 36×10-3) = (1700-1600) Ea8
314

-5 9914 × 8 314 = -0 00024
Ea
Ea = 207552 082 J mol-1 or 207 5 kJ
mol-1

If rate constant of a reaction is 1.6×10^(-5) and 6.36×10^(-3) per second at 600K and 700K, calculate activation energy for reaction.