# If S=1/3 ft3, f has the dimension of?

Here the dimension of S is [L] and t is [T]
so dimension of s is $f=\frac{\left[S\right]}{\left[{t}^{3}\right]}=\frac{\left[L\right]}{\left[{T}^{3}\right]}=\left[L{T}^{-3}\right]$.

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