# If sin^6x = 1 + cos^4(3x) then find the general solution of x.

ik its a very late response but it can help others like me who got this question doubt

I still solved it with help from mentor

-1 <= sin x <= 1

0<= sin ^2n x<= 1

sin^6 x = 1

sinx = + - 1

x= 2n TT + TT/2 ---------------------------- 1

cos ^4 3x=0

cos 3x= 0

3x= 2nTT - + TT/ 2

x= 2nTT/ 3 - + TT/ 6 -------------------- 2

Thus, the general equation is:

x= nTT + TT / 2

thus the equation is: (2n+ 1) TT / 2

::HAPPY SOLVING ::