If Sin A=3/5 and Cos B = 9/41, Find the value of Sin (A-B) and Cos(A+B) - Maths - Trigonometric Functions

Question

If Sin A=3/5 and Cos B = 9/41, Find the value of Sin (A-B) and
Cos(A+B)

Ashwini Kumar · Accepted Answer

We have,      sin A=35⇒cos A=1-sin2A=1-352=45cos B=941⇒sin B=1-cos2B=1-9412=4041Now,    sinA-B=sin A cos B-cos A sin B=35×941-45×4041=27205-160205=-133205cosA+B=cos A cos B-sin A sin B=45×941-35×4041=36205-120205=-84205